(0.03-0.21x+0.3x^2)=2X

Solution for (0.03-0.21x+0.3x^2)=2X equation:

(0.03-0.21x+0.3x^2)=2x

We move all terms to the left:

(0.03-0.21x+0.3x^2)-(2x)=0

We get rid of parentheses

0.3x^2-0.21x-2x+0.03=0

We add all the numbers together, and all the variables

0.3x^2-2.21x+0.03=0

a = 0.3; b = -2.21; c = +0.03;
Δ = b2-4ac
Δ = -2.212-4·0.3·0.03
Δ = 4.8481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.21)-\sqrt{4.8481}}{2*0.3}=\frac{2.21-\sqrt{4.8481}}{0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.21)+\sqrt{4.8481}}{2*0.3}=\frac{2.21+\sqrt{4.8481}}{0.6}
$